Series Circuit Question?
by Jessica on Jan.06, 2012, under Multimeter
Series Circuit Question?
I have been trying this question for some time now and I don’t think there is a way to answer it, but I could be mistaken. Here is the question word for word,
“When an ammeter A is added to a circuit to measure the current its acts as a series resistor
of resistance R. The circuit of Figure 3 consists of a 6.0V supply of negligible internal resistance
connected to two equal resistors and the 0-100 mA ammeter A.
a) Write down the total resistance in the circuit:
(i)before, and (ii) after the ammeter is added
b) Show that the current before the ammeter is added is 30mA
c) The ammeter reads 20mA when it is in the circuit. Calculate its resistance R
d) A perfect ammenter shouldn’t alter the current it is measuring. Suggest the best value
of the resistance R to make the ammeter perfect. ”
I think the course I am on assumes that the circuit is a DC power supply. The only answer that really stumps me is the very first question.
I have the answers but I want to know the intermediate steps to the answer. The answers are for the questions are: ” 4 a) i) 200 ohms ii) 200ohms + R c) 100ohms d) infinite”
As I said I only really need help on the first part but thought you might need the whole question.
Thank you very much in advance.
EDIT: I feel like a donkey’s arse, you are totally right Figure 3 does show the circuit, and shows the resistors with 100ohms, I suppose my brain is slowing down. Thanks for all your help